Base | Representation |
---|---|
bin | 100101001111010100000… |
… | …0100011010000100011111 |
3 | 200010021202222121100112202 |
4 | 1022132220010122010133 |
5 | 1132323410144332213 |
6 | 14515122353522115 |
7 | 1035525633205106 |
oct | 112365004320437 |
9 | 20107688540482 |
10 | 5118125777183 |
11 | 16a3648632301 |
12 | 6a7b15b7333b |
13 | 2b1838ba1943 |
14 | 139a0bc1503d |
15 | 8d202dabb58 |
hex | 4a7a811a11f |
5118125777183 has 2 divisors, whose sum is σ = 5118125777184. Its totient is φ = 5118125777182.
The previous prime is 5118125777173. The next prime is 5118125777201. The reversal of 5118125777183 is 3817775218115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5118125777183 - 232 = 5113830809887 is a prime.
It is a super-2 number, since 2×51181257771832 (a number of 26 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5118125777173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2559062888591 + 2559062888592.
It is an arithmetic number, because the mean of its divisors is an integer number (2559062888592).
Almost surely, 25118125777183 is an apocalyptic number.
5118125777183 is a deficient number, since it is larger than the sum of its proper divisors (1).
5118125777183 is an equidigital number, since it uses as much as digits as its factorization.
5118125777183 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3292800, while the sum is 56.
The spelling of 5118125777183 in words is "five trillion, one hundred eighteen billion, one hundred twenty-five million, seven hundred seventy-seven thousand, one hundred eighty-three".
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