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5118150517141 is a prime number
BaseRepresentation
bin100101001111010100110…
…0010110010000110010101
3200010021211201011021101111
41022132221202302012111
51132323433013022031
614515125040055021
71035526353405214
oct112365142620625
920107751137344
105118150517141
1116a366059a852
126a7b22304471
132b184105467c
14139a1121507b
158d2051471b1
hex4a7a98b2195

5118150517141 has 2 divisors, whose sum is σ = 5118150517142. Its totient is φ = 5118150517140.

The previous prime is 5118150517127. The next prime is 5118150517147. The reversal of 5118150517141 is 1417150518115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4022716160241 + 1095434356900 = 2005671^2 + 1046630^2 .

It is a cyclic number.

It is not a de Polignac number, because 5118150517141 - 29 = 5118150516629 is a prime.

It is a super-2 number, since 2×51181505171412 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5118150517094 and 5118150517103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5118150517147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2559075258570 + 2559075258571.

It is an arithmetic number, because the mean of its divisors is an integer number (2559075258571).

Almost surely, 25118150517141 is an apocalyptic number.

It is an amenable number.

5118150517141 is a deficient number, since it is larger than the sum of its proper divisors (1).

5118150517141 is an equidigital number, since it uses as much as digits as its factorization.

5118150517141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28000, while the sum is 40.

The spelling of 5118150517141 in words is "five trillion, one hundred eighteen billion, one hundred fifty million, five hundred seventeen thousand, one hundred forty-one".