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51182549096821 is a prime number
BaseRepresentation
bin10111010001100110111011…
…01010000101100101110101
320201020000002211220122022221
423220303131222011211311
523202033330032044241
6300504534412322341
713531550165042332
oct1350633552054565
9221200084818287
1051182549096821
111534344070334a
1258a76301733b1
13227365579276c
14c8d36a1db989
155db5977a75d1
hex2e8cdda85975

51182549096821 has 2 divisors, whose sum is σ = 51182549096822. Its totient is φ = 51182549096820.

The previous prime is 51182549096773. The next prime is 51182549096843. The reversal of 51182549096821 is 12869094528115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51052382559025 + 130166537796 = 7145095^2 + 360786^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51182549096821 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 51182549096821.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51182549096321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25591274548410 + 25591274548411.

It is an arithmetic number, because the mean of its divisors is an integer number (25591274548411).

Almost surely, 251182549096821 is an apocalyptic number.

It is an amenable number.

51182549096821 is a deficient number, since it is larger than the sum of its proper divisors (1).

51182549096821 is an equidigital number, since it uses as much as digits as its factorization.

51182549096821 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12441600, while the sum is 61.

The spelling of 51182549096821 in words is "fifty-one trillion, one hundred eighty-two billion, five hundred forty-nine million, ninety-six thousand, eight hundred twenty-one".