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5119973 is a prime number
BaseRepresentation
bin10011100001111111100101
3100122010021122
4103201333211
52302314343
6301423325
761343015
oct23417745
910563248
105119973
112987791
12186ab45
1310a3591
14973c45
156b2068
hex4e1fe5

5119973 has 2 divisors, whose sum is σ = 5119974. Its totient is φ = 5119972.

The previous prime is 5119969. The next prime is 5119997. The reversal of 5119973 is 3799115.

5119973 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2982529 + 2137444 = 1727^2 + 1462^2 .

It is a cyclic number.

It is not a de Polignac number, because 5119973 - 22 = 5119969 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5119963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2559986 + 2559987.

It is an arithmetic number, because the mean of its divisors is an integer number (2559987).

Almost surely, 25119973 is an apocalyptic number.

It is an amenable number.

5119973 is a deficient number, since it is larger than the sum of its proper divisors (1).

5119973 is an equidigital number, since it uses as much as digits as its factorization.

5119973 is an evil number, because the sum of its binary digits is even.

The product of its digits is 8505, while the sum is 35.

The square root of 5119973 is about 2262.7357335756. The cubic root of 5119973 is about 172.3544722346.

It can be divided in two parts, 511997 and 3, that added together give a cube (512000 = 803).

The spelling of 5119973 in words is "five million, one hundred nineteen thousand, nine hundred seventy-three".