Base | Representation |
---|---|
bin | 101111101011110000… |
… | …010011100000110101 |
3 | 11220011012201212222222 |
4 | 233223300103200311 |
5 | 1314324141330403 |
6 | 35304304332125 |
7 | 3461532245624 |
oct | 575360234065 |
9 | 156135655888 |
10 | 51199948853 |
11 | 1a794044419 |
12 | 9b0a914045 |
13 | 4a9c546b31 |
14 | 2699c496bb |
15 | 14e9dc0338 |
hex | bebc13835 |
51199948853 has 2 divisors, whose sum is σ = 51199948854. Its totient is φ = 51199948852.
The previous prime is 51199948771. The next prime is 51199948871. The reversal of 51199948853 is 35884999115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 50553924964 + 646023889 = 224842^2 + 25417^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51199948853 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51199942853) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25599974426 + 25599974427.
It is an arithmetic number, because the mean of its divisors is an integer number (25599974427).
Almost surely, 251199948853 is an apocalyptic number.
It is an amenable number.
51199948853 is a deficient number, since it is larger than the sum of its proper divisors (1).
51199948853 is an equidigital number, since it uses as much as digits as its factorization.
51199948853 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 13996800, while the sum is 62.
The spelling of 51199948853 in words is "fifty-one billion, one hundred ninety-nine million, nine hundred forty-eight thousand, eight hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •