Base | Representation |
---|---|
bin | 111010001101010011010000… |
… | …0110000101101110110011110 |
3 | 2111010211212020121200220210002 |
4 | 1310122212200300231312132 |
5 | 1014102112434044423032 |
6 | 5012534115353414302 |
7 | 212562612213564644 |
oct | 16432464060556636 |
9 | 2433755217626702 |
10 | 512001453514142 |
11 | 139159662727329 |
12 | 4951138aa0a392 |
13 | 18c8c6b724aac7 |
14 | 90610070bb194 |
15 | 3e2d4ed234862 |
hex | 1d1a9a0c2dd9e |
512001453514142 has 8 divisors (see below), whose sum is σ = 771981466179936. Its totient is φ = 254674298120832.
The previous prime is 512001453514127. The next prime is 512001453514319. The reversal of 512001453514142 is 241415354100215.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×5120014535141422 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 512001453514096 and 512001453514105.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 663214317638 + ... + 663214318409.
It is an arithmetic number, because the mean of its divisors is an integer number (96497683272492).
Almost surely, 2512001453514142 is an apocalyptic number.
512001453514142 is a deficient number, since it is larger than the sum of its proper divisors (259980012665794).
512001453514142 is a wasteful number, since it uses less digits than its factorization.
512001453514142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1326428636242.
The product of its (nonzero) digits is 96000, while the sum is 38.
The spelling of 512001453514142 in words is "five hundred twelve trillion, one billion, four hundred fifty-three million, five hundred fourteen thousand, one hundred forty-two".
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