5120113 has 2 divisors, whose sum is σ = 5120114. Its totient is φ = 5120112.

The previous prime is 5120051. The next prime is 5120117. The reversal of 5120113 is 3110215.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4524129 + 595984 = 2127^2 + 772^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-5120113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5120093 and 5120102.

It is not a weakly prime, because it can be changed into another prime (5120117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2560056 + 2560057.

It is an arithmetic number, because the mean of its divisors is an integer number (2560057).

Almost surely, 2^5120113 is an apocalyptic number.

It is an amenable number.

5120113 is a deficient number, since it is larger than the sum of its proper divisors (1).

5120113 is an equidigital number, since it uses as much as digits as its factorization.

5120113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30, while the sum is 13.

The square root of 5120113 is about 2262.7666693674. The cubic root of 5120113 is about 172.3560431678.

Adding to 5120113 its reverse (3110215), we get a palindrome (8230328).

It can be divided in two parts, 51 and 20113, that added together give a square (20164 = 142²).

The spelling of 5120113 in words is "five million, one hundred twenty thousand, one hundred thirteen".