Base | Representation |
---|---|
bin | 11110100001001… |
… | …011001100001111 |
3 | 1022200102221220002 |
4 | 132201023030033 |
5 | 2022033404241 |
6 | 122450114515 |
7 | 15455016323 |
oct | 3641131417 |
9 | 1280387802 |
10 | 512013071 |
11 | 243021aa9 |
12 | 12357ba3b |
13 | 8210001b |
14 | 4c001983 |
15 | 2ee3c89b |
hex | 1e84b30f |
512013071 has 2 divisors, whose sum is σ = 512013072. Its totient is φ = 512013070.
The previous prime is 512013059. The next prime is 512013079. The reversal of 512013071 is 170310215.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 512013071 - 210 = 512012047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (512013079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256006535 + 256006536.
It is an arithmetic number, because the mean of its divisors is an integer number (256006536).
Almost surely, 2512013071 is an apocalyptic number.
512013071 is a deficient number, since it is larger than the sum of its proper divisors (1).
512013071 is an equidigital number, since it uses as much as digits as its factorization.
512013071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 210, while the sum is 20.
The square root of 512013071 is about 22627.7058271492. The cubic root of 512013071 is about 800.0068077546.
Adding to 512013071 its reverse (170310215), we get a palindrome (682323286).
The spelling of 512013071 in words is "five hundred twelve million, thirteen thousand, seventy-one".
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