Base | Representation |
---|---|
bin | 111010001101011010000100… |
… | …1111100100000001101011100 |
3 | 2111010220021001120111200020110 |
4 | 1310122310021330200031130 |
5 | 1014102332434344113224 |
6 | 5012544541153250020 |
7 | 212563641230251230 |
oct | 16432641174401534 |
9 | 2433807046450213 |
10 | 512016103113564 |
11 | 13916489aa80195 |
12 | 49514198b63910 |
13 | 18c90bb030052a |
14 | 90619d696c5c0 |
15 | 3e2daa93d1929 |
hex | 1d1ad09f2035c |
512016103113564 has 24 divisors (see below), whose sum is σ = 1365376274969728. Its totient is φ = 146290315175280.
The previous prime is 512016103113527. The next prime is 512016103113587. The reversal of 512016103113564 is 465311301610215.
It is a super-3 number, since 3×5120161031135643 (a number of 45 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3047714899402 + ... + 3047714899569.
Almost surely, 2512016103113564 is an apocalyptic number.
It is an amenable number.
512016103113564 is an abundant number, since it is smaller than the sum of its proper divisors (853360171856164).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
512016103113564 is a wasteful number, since it uses less digits than its factorization.
512016103113564 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6095429798985 (or 6095429798983 counting only the distinct ones).
The product of its (nonzero) digits is 64800, while the sum is 39.
Adding to 512016103113564 its reverse (465311301610215), we get a palindrome (977327404723779).
The spelling of 512016103113564 in words is "five hundred twelve trillion, sixteen billion, one hundred three million, one hundred thirteen thousand, five hundred sixty-four".
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