Base | Representation |
---|---|
bin | 1100001101010… |
… | …0110001001011 |
3 | 10120100101111212 |
4 | 3003110301023 |
5 | 101102000042 |
6 | 5025243335 |
7 | 1161135212 |
oct | 303246113 |
9 | 116311455 |
10 | 51203147 |
11 | 269a2756 |
12 | 1519354b |
13 | a7b9c28 |
14 | 6b2c079 |
15 | 4766482 |
hex | 30d4c4b |
51203147 has 2 divisors, whose sum is σ = 51203148. Its totient is φ = 51203146.
The previous prime is 51203123. The next prime is 51203171. The reversal of 51203147 is 74130215.
It is a balanced prime because it is at equal distance from previous prime (51203123) and next prime (51203171).
It is a cyclic number.
It is not a de Polignac number, because 51203147 - 214 = 51186763 is a prime.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (51203177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25601573 + 25601574.
It is an arithmetic number, because the mean of its divisors is an integer number (25601574).
Almost surely, 251203147 is an apocalyptic number.
51203147 is a deficient number, since it is larger than the sum of its proper divisors (1).
51203147 is an equidigital number, since it uses as much as digits as its factorization.
51203147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 840, while the sum is 23.
The square root of 51203147 is about 7155.6374279305. The cubic root of 51203147 is about 371.3347143874.
The spelling of 51203147 in words is "fifty-one million, two hundred three thousand, one hundred forty-seven".
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