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51204213636497 is a prime number
BaseRepresentation
bin10111010010001111010001…
…11101101111110110010001
320201022002000200120021202022
423221013220331233312101
523202412212142331442
6300522520242501225
713533245101431515
oct1351075075576621
9221262020507668
1051204213636497
1115351648785699
1258ab877664815
1322756c8c7c4cc
14c904235b8145
155dbe147203d2
hex2e91e8f6fd91

51204213636497 has 2 divisors, whose sum is σ = 51204213636498. Its totient is φ = 51204213636496.

The previous prime is 51204213636427. The next prime is 51204213636517. The reversal of 51204213636497 is 79463631240215.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47969974673296 + 3234238963201 = 6926036^2 + 1798399^2 .

It is a cyclic number.

It is not a de Polignac number, because 51204213636497 - 210 = 51204213635473 is a prime.

It is not a weakly prime, because it can be changed into another prime (51204213636427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25602106818248 + 25602106818249.

It is an arithmetic number, because the mean of its divisors is an integer number (25602106818249).

Almost surely, 251204213636497 is an apocalyptic number.

It is an amenable number.

51204213636497 is a deficient number, since it is larger than the sum of its proper divisors (1).

51204213636497 is an equidigital number, since it uses as much as digits as its factorization.

51204213636497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6531840, while the sum is 53.

The spelling of 51204213636497 in words is "fifty-one trillion, two hundred four billion, two hundred thirteen million, six hundred thirty-six thousand, four hundred ninety-seven".