Base | Representation |
---|---|
bin | 100101010000011001001… |
… | …0000011111101000111011 |
3 | 200010111202120010111212012 |
4 | 1022200302100133220323 |
5 | 1132343132203422111 |
6 | 14520144413440135 |
7 | 1035640244403551 |
oct | 112406220375073 |
9 | 20114676114765 |
10 | 5120444201531 |
11 | 16a462829788a |
12 | 6a84624a004b |
13 | 2b1b182c7c79 |
14 | 139b8babbbd1 |
15 | 8d2db6bc48b |
hex | 4a83241fa3b |
5120444201531 has 2 divisors, whose sum is σ = 5120444201532. Its totient is φ = 5120444201530.
The previous prime is 5120444201491. The next prime is 5120444201611. The reversal of 5120444201531 is 1351024440215.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5120444201531 - 210 = 5120444200507 is a prime.
It is a super-2 number, since 2×51204442015312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5120444206531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2560222100765 + 2560222100766.
It is an arithmetic number, because the mean of its divisors is an integer number (2560222100766).
Almost surely, 25120444201531 is an apocalyptic number.
5120444201531 is a deficient number, since it is larger than the sum of its proper divisors (1).
5120444201531 is an equidigital number, since it uses as much as digits as its factorization.
5120444201531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19200, while the sum is 32.
Adding to 5120444201531 its reverse (1351024440215), we get a palindrome (6471468641746).
The spelling of 5120444201531 in words is "five trillion, one hundred twenty billion, four hundred forty-four million, two hundred one thousand, five hundred thirty-one".
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