Base | Representation |
---|---|
bin | 10111010010011010010100… |
… | …11101011101001111011111 |
3 | 20201022122100000011112001122 |
4 | 23221031022131131033133 |
5 | 23203011333420244033 |
6 | 300525340541401155 |
7 | 13533545054332544 |
oct | 1351151235351737 |
9 | 221278300145048 |
10 | 51210144306143 |
11 | 15354111462569 |
12 | 58b0a518691bb |
13 | 22761328824a4 |
14 | c908270dabcb |
15 | 5dc160210a98 |
hex | 2e934a75d3df |
51210144306143 has 2 divisors, whose sum is σ = 51210144306144. Its totient is φ = 51210144306142.
The previous prime is 51210144306133. The next prime is 51210144306149. The reversal of 51210144306143 is 34160344101215.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51210144306143 - 230 = 51209070564319 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51210144306149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25605072153071 + 25605072153072.
It is an arithmetic number, because the mean of its divisors is an integer number (25605072153072).
Almost surely, 251210144306143 is an apocalyptic number.
51210144306143 is a deficient number, since it is larger than the sum of its proper divisors (1).
51210144306143 is an equidigital number, since it uses as much as digits as its factorization.
51210144306143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34560, while the sum is 35.
Adding to 51210144306143 its reverse (34160344101215), we get a palindrome (85370488407358).
The spelling of 51210144306143 in words is "fifty-one trillion, two hundred ten billion, one hundred forty-four million, three hundred six thousand, one hundred forty-three".
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