Base | Representation |
---|---|
bin | 111010001110010001101000… |
… | …1110011000111010011100010 |
3 | 2111011022200000222200022112001 |
4 | 1310130203101303013103202 |
5 | 1014111311320033244300 |
6 | 5013115433012554214 |
7 | 212605364064666256 |
oct | 16434432163072342 |
9 | 2434280028608461 |
10 | 512135420212450 |
11 | 139200459404621 |
12 | 4953333802296a |
13 | 18c9c216b842a8 |
14 | 90676b530c266 |
15 | 3e31c3e44116a |
hex | 1d1c8d1cc74e2 |
512135420212450 has 12 divisors (see below), whose sum is σ = 952571881595250. Its totient is φ = 204854168084960.
The previous prime is 512135420212289. The next prime is 512135420212499. The reversal of 512135420212450 is 54212024531215.
It can be written as a sum of positive squares in 3 ways, for example, as 338613840540369 + 173521579672081 = 18401463^2 + 13172759^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 5121354202075 + ... + 5121354202174.
Almost surely, 2512135420212450 is an apocalyptic number.
512135420212450 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
512135420212450 is a deficient number, since it is larger than the sum of its proper divisors (440436461382800).
512135420212450 is a wasteful number, since it uses less digits than its factorization.
512135420212450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10242708404261 (or 10242708404256 counting only the distinct ones).
The product of its (nonzero) digits is 96000, while the sum is 37.
Adding to 512135420212450 its reverse (54212024531215), we get a palindrome (566347444743665).
The spelling of 512135420212450 in words is "five hundred twelve trillion, one hundred thirty-five billion, four hundred twenty million, two hundred twelve thousand, four hundred fifty".
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