Base | Representation |
---|---|
bin | 100101010000111011101… |
… | …1100000010010001000101 |
3 | 200010121202110002210220021 |
4 | 1022201313130002101011 |
5 | 1132403021320323403 |
6 | 14520455514335141 |
7 | 1036011066654514 |
oct | 112416734022105 |
9 | 20117673083807 |
10 | 5121604854853 |
11 | 16a5073469903 |
12 | 6a872712a4b1 |
13 | 2b1c718c4096 |
14 | 139c5bcc867b |
15 | 8d3585348bd |
hex | 4a877702445 |
5121604854853 has 2 divisors, whose sum is σ = 5121604854854. Its totient is φ = 5121604854852.
The previous prime is 5121604854833. The next prime is 5121604854911. The reversal of 5121604854853 is 3584584061215.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4338480741604 + 783124113249 = 2082902^2 + 884943^2 .
It is a cyclic number.
It is not a de Polignac number, because 5121604854853 - 29 = 5121604854341 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5121604854853.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5121604854833) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2560802427426 + 2560802427427.
It is an arithmetic number, because the mean of its divisors is an integer number (2560802427427).
Almost surely, 25121604854853 is an apocalyptic number.
It is an amenable number.
5121604854853 is a deficient number, since it is larger than the sum of its proper divisors (1).
5121604854853 is an equidigital number, since it uses as much as digits as its factorization.
5121604854853 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608000, while the sum is 52.
The spelling of 5121604854853 in words is "five trillion, one hundred twenty-one billion, six hundred four million, eight hundred fifty-four thousand, eight hundred fifty-three".
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