Base | Representation |
---|---|
bin | 100101010001001011101… |
… | …0110110001010110000101 |
3 | 200010200010202201120021211 |
4 | 1022202113112301112011 |
5 | 1132410120412030413 |
6 | 14521025004011421 |
7 | 1036030261366435 |
oct | 112422726612605 |
9 | 20120122646254 |
10 | 5122140345733 |
11 | 16a5318767054 |
12 | 6a8856530b71 |
13 | 2b20288244a8 |
14 | 139cad07c2c5 |
15 | 8d38a55d83d |
hex | 4a8975b1585 |
5122140345733 has 2 divisors, whose sum is σ = 5122140345734. Its totient is φ = 5122140345732.
The previous prime is 5122140345691. The next prime is 5122140345787. The reversal of 5122140345733 is 3375430412215.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5120254788804 + 1885556929 = 2262798^2 + 43423^2 .
It is a cyclic number.
It is not a de Polignac number, because 5122140345733 - 213 = 5122140337541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5122140342733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2561070172866 + 2561070172867.
It is an arithmetic number, because the mean of its divisors is an integer number (2561070172867).
Almost surely, 25122140345733 is an apocalyptic number.
It is an amenable number.
5122140345733 is a deficient number, since it is larger than the sum of its proper divisors (1).
5122140345733 is an equidigital number, since it uses as much as digits as its factorization.
5122140345733 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 302400, while the sum is 40.
Adding to 5122140345733 its reverse (3375430412215), we get a palindrome (8497570757948).
The spelling of 5122140345733 in words is "five trillion, one hundred twenty-two billion, one hundred forty million, three hundred forty-five thousand, seven hundred thirty-three".
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