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5122140345733 is a prime number
BaseRepresentation
bin100101010001001011101…
…0110110001010110000101
3200010200010202201120021211
41022202113112301112011
51132410120412030413
614521025004011421
71036030261366435
oct112422726612605
920120122646254
105122140345733
1116a5318767054
126a8856530b71
132b20288244a8
14139cad07c2c5
158d38a55d83d
hex4a8975b1585

5122140345733 has 2 divisors, whose sum is σ = 5122140345734. Its totient is φ = 5122140345732.

The previous prime is 5122140345691. The next prime is 5122140345787. The reversal of 5122140345733 is 3375430412215.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5120254788804 + 1885556929 = 2262798^2 + 43423^2 .

It is a cyclic number.

It is not a de Polignac number, because 5122140345733 - 213 = 5122140337541 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5122140342733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2561070172866 + 2561070172867.

It is an arithmetic number, because the mean of its divisors is an integer number (2561070172867).

Almost surely, 25122140345733 is an apocalyptic number.

It is an amenable number.

5122140345733 is a deficient number, since it is larger than the sum of its proper divisors (1).

5122140345733 is an equidigital number, since it uses as much as digits as its factorization.

5122140345733 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 302400, while the sum is 40.

Adding to 5122140345733 its reverse (3375430412215), we get a palindrome (8497570757948).

The spelling of 5122140345733 in words is "five trillion, one hundred twenty-two billion, one hundred forty million, three hundred forty-five thousand, seven hundred thirty-three".