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51221503204153 is a prime number
BaseRepresentation
bin10111010010101111011111…
…00000001101101100111001
320201100201122121221022210221
423221113233200031230321
523203203114310013103
6300534500030140041
713534426412352352
oct1351275740155471
9221321577838727
1051221503204153
1115358a10242787
1258b30a1951621
132277222c5a109
14c911c3912d29
155dc5c75451bd
hex2e95ef80db39

51221503204153 has 2 divisors, whose sum is σ = 51221503204154. Its totient is φ = 51221503204152.

The previous prime is 51221503204121. The next prime is 51221503204229. The reversal of 51221503204153 is 35140230512215.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 49972287915664 + 1249215288489 = 7069108^2 + 1117683^2 .

It is a cyclic number.

It is not a de Polignac number, because 51221503204153 - 25 = 51221503204121 is a prime.

It is a super-3 number, since 3×512215032041533 (a number of 42 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (51221503204453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25610751602076 + 25610751602077.

It is an arithmetic number, because the mean of its divisors is an integer number (25610751602077).

Almost surely, 251221503204153 is an apocalyptic number.

It is an amenable number.

51221503204153 is a deficient number, since it is larger than the sum of its proper divisors (1).

51221503204153 is an equidigital number, since it uses as much as digits as its factorization.

51221503204153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36000, while the sum is 34.

Adding to 51221503204153 its reverse (35140230512215), we get a palindrome (86361733716368).

The spelling of 51221503204153 in words is "fifty-one trillion, two hundred twenty-one billion, five hundred three million, two hundred four thousand, one hundred fifty-three".