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51225303540401 is a prime number
BaseRepresentation
bin10111010010110110100100…
…00001010110001010110001
320201101002110110221102002022
423221123102001112022301
523203233410201243101
6300540325104401225
713534622526602024
oct1351332201261261
9221332413842068
1051225303540401
111535a590453641
1258b3982616215
1322776aa3b15a3
14c914645311bb
155dc74aecaa1b
hex2e96d20562b1

51225303540401 has 2 divisors, whose sum is σ = 51225303540402. Its totient is φ = 51225303540400.

The previous prime is 51225303540379. The next prime is 51225303540403. The reversal of 51225303540401 is 10404530352215.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51147899954176 + 77403586225 = 7151776^2 + 278215^2 .

It is a cyclic number.

It is not a de Polignac number, because 51225303540401 - 222 = 51225299346097 is a prime.

Together with 51225303540403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (51225303540403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25612651770200 + 25612651770201.

It is an arithmetic number, because the mean of its divisors is an integer number (25612651770201).

Almost surely, 251225303540401 is an apocalyptic number.

It is an amenable number.

51225303540401 is a deficient number, since it is larger than the sum of its proper divisors (1).

51225303540401 is an equidigital number, since it uses as much as digits as its factorization.

51225303540401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72000, while the sum is 35.

Adding to 51225303540401 its reverse (10404530352215), we get a palindrome (61629833892616).

The spelling of 51225303540401 in words is "fifty-one trillion, two hundred twenty-five billion, three hundred three million, five hundred forty thousand, four hundred one".