Base | Representation |
---|---|
bin | 100101010001101110010… |
… | …0111010100010111101011 |
3 | 200010210010202011112112101 |
4 | 1022203130213110113223 |
5 | 1132420010342431103 |
6 | 14521340152554231 |
7 | 1036101131054443 |
oct | 112433447242753 |
9 | 20123122145471 |
10 | 5123302311403 |
11 | 16a5864655061 |
12 | 6a8b1b6b2977 |
13 | 2b218248ca43 |
14 | 139d7d50b123 |
15 | 8d407584a1d |
hex | 4a8dc9d45eb |
5123302311403 has 2 divisors, whose sum is σ = 5123302311404. Its totient is φ = 5123302311402.
The previous prime is 5123302311373. The next prime is 5123302311427. The reversal of 5123302311403 is 3041132033215.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5123302311403 - 217 = 5123302180331 is a prime.
It is a super-3 number, since 3×51233023114033 (a number of 39 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (5123302311203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2561651155701 + 2561651155702.
It is an arithmetic number, because the mean of its divisors is an integer number (2561651155702).
Almost surely, 25123302311403 is an apocalyptic number.
5123302311403 is a deficient number, since it is larger than the sum of its proper divisors (1).
5123302311403 is an equidigital number, since it uses as much as digits as its factorization.
5123302311403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 5123302311403 its reverse (3041132033215), we get a palindrome (8164434344618).
The spelling of 5123302311403 in words is "five trillion, one hundred twenty-three billion, three hundred two million, three hundred eleven thousand, four hundred three".
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