Base | Representation |
---|---|
bin | 1110111010011100010… |
… | …10100100000100000111 |
3 | 1210222121220112001112022 |
4 | 13131032022210010013 |
5 | 31343410100001411 |
6 | 1031222110113355 |
7 | 52010026246562 |
oct | 7351612440407 |
9 | 1728556461468 |
10 | 512412500231 |
11 | 188349552655 |
12 | 83385aab85b |
13 | 394218ac778 |
14 | 1ab2d93b4d9 |
15 | d4e06d5edb |
hex | 774e2a4107 |
512412500231 has 2 divisors, whose sum is σ = 512412500232. Its totient is φ = 512412500230.
The previous prime is 512412500207. The next prime is 512412500261. The reversal of 512412500231 is 132005214215.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 512412500231 - 218 = 512412238087 is a prime.
It is a super-2 number, since 2×5124125002312 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 512412500231.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (512412500261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256206250115 + 256206250116.
It is an arithmetic number, because the mean of its divisors is an integer number (256206250116).
Almost surely, 2512412500231 is an apocalyptic number.
512412500231 is a deficient number, since it is larger than the sum of its proper divisors (1).
512412500231 is an equidigital number, since it uses as much as digits as its factorization.
512412500231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2400, while the sum is 26.
Adding to 512412500231 its reverse (132005214215), we get a palindrome (644417714446).
The spelling of 512412500231 in words is "five hundred twelve billion, four hundred twelve million, five hundred thousand, two hundred thirty-one".
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