Base | Representation |
---|---|
bin | 100101010010001111011… |
… | …1000000101001111101001 |
3 | 200010220000020000021112212 |
4 | 1022210132320011033221 |
5 | 1132424244441032103 |
6 | 14522042344214505 |
7 | 1036140520221365 |
oct | 112443670051751 |
9 | 20126006007485 |
10 | 5124414002153 |
11 | 16a6285124846 |
12 | 6a918ba6a435 |
13 | 2b22cb8a4a14 |
14 | 13a0470102a5 |
15 | 8d46ee797d8 |
hex | 4a91ee053e9 |
5124414002153 has 2 divisors, whose sum is σ = 5124414002154. Its totient is φ = 5124414002152.
The previous prime is 5124414002131. The next prime is 5124414002297. The reversal of 5124414002153 is 3512004144215.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3337625724889 + 1786788277264 = 1826917^2 + 1336708^2 .
It is a cyclic number.
It is not a de Polignac number, because 5124414002153 - 210 = 5124414001129 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (5124414001153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2562207001076 + 2562207001077.
It is an arithmetic number, because the mean of its divisors is an integer number (2562207001077).
Almost surely, 25124414002153 is an apocalyptic number.
It is an amenable number.
5124414002153 is a deficient number, since it is larger than the sum of its proper divisors (1).
5124414002153 is an equidigital number, since it uses as much as digits as its factorization.
5124414002153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19200, while the sum is 32.
Adding to 5124414002153 its reverse (3512004144215), we get a palindrome (8636418146368).
The spelling of 5124414002153 in words is "five trillion, one hundred twenty-four billion, four hundred fourteen million, two thousand, one hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •