Base | Representation |
---|---|
bin | 10111010011011100010010… |
… | …10000101110001001000111 |
3 | 20201110000202000122211020212 |
4 | 23221232021100232021013 |
5 | 23204101400230423341 |
6 | 300553514552550035 |
7 | 13536240456061643 |
oct | 1351561120561107 |
9 | 221400660584225 |
10 | 51245557670471 |
11 | 1536813437730a |
12 | 58b78956b231b |
13 | 2279587616738 |
14 | c92426489c23 |
15 | 5dd0341e45eb |
hex | 2e9b8942e247 |
51245557670471 has 2 divisors, whose sum is σ = 51245557670472. Its totient is φ = 51245557670470.
The previous prime is 51245557670441. The next prime is 51245557670497. The reversal of 51245557670471 is 17407675554215.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51245557670471 is a prime.
It is a super-3 number, since 3×512455576704713 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 51245557670471.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51245557670441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25622778835235 + 25622778835236.
It is an arithmetic number, because the mean of its divisors is an integer number (25622778835236).
Almost surely, 251245557670471 is an apocalyptic number.
51245557670471 is a deficient number, since it is larger than the sum of its proper divisors (1).
51245557670471 is an equidigital number, since it uses as much as digits as its factorization.
51245557670471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41160000, while the sum is 59.
The spelling of 51245557670471 in words is "fifty-one trillion, two hundred forty-five billion, five hundred fifty-seven million, six hundred seventy thousand, four hundred seventy-one".
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