Base | Representation |
---|---|
bin | 100101010010100100000… |
… | …0000110100110001001001 |
3 | 200010221210022122220212211 |
4 | 1022211020000310301021 |
5 | 1132432203131103232 |
6 | 14522235040505121 |
7 | 1036163600401015 |
oct | 112451000646111 |
9 | 20127708586784 |
10 | 5125104159817 |
11 | 16a65a9761484 |
12 | 6a934301b1a1 |
13 | 2b23ab879235 |
14 | 13a0b0945545 |
15 | 8d4b0855a47 |
hex | 4a948034c49 |
5125104159817 has 2 divisors, whose sum is σ = 5125104159818. Its totient is φ = 5125104159816.
The previous prime is 5125104159793. The next prime is 5125104159863. The reversal of 5125104159817 is 7189514015215.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4935377708041 + 189726451776 = 2221571^2 + 435576^2 .
It is a cyclic number.
It is not a de Polignac number, because 5125104159817 - 27 = 5125104159689 is a prime.
It is not a weakly prime, because it can be changed into another prime (5125104159017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2562552079908 + 2562552079909.
It is an arithmetic number, because the mean of its divisors is an integer number (2562552079909).
Almost surely, 25125104159817 is an apocalyptic number.
It is an amenable number.
5125104159817 is a deficient number, since it is larger than the sum of its proper divisors (1).
5125104159817 is an equidigital number, since it uses as much as digits as its factorization.
5125104159817 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504000, while the sum is 49.
The spelling of 5125104159817 in words is "five trillion, one hundred twenty-five billion, one hundred four million, one hundred fifty-nine thousand, eight hundred seventeen".
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