Base | Representation |
---|---|
bin | 100101010010101001110… |
… | …1110001100111101000011 |
3 | 200010222022000022100122200 |
4 | 1022211103232030331003 |
5 | 1132433103423322424 |
6 | 14522310335204243 |
7 | 1036201504220520 |
oct | 112452356147503 |
9 | 20128260270580 |
10 | 5125300604739 |
11 | 16a669a636457 |
12 | 6a9398976683 |
13 | 2b241048a333 |
14 | 13a0cca80147 |
15 | 8d4c2c0b8c9 |
hex | 4a953b8cf43 |
5125300604739 has 96 divisors (see below), whose sum is σ = 9161904660480. Its totient is φ = 2694044814336.
The previous prime is 5125300604659. The next prime is 5125300604791. The reversal of 5125300604739 is 9374060035215.
5125300604739 is a `hidden beast` number, since 5 + 1 + 2 + 5 + 3 + 0 + 0 + 604 + 7 + 39 = 666.
It is not a de Polignac number, because 5125300604739 - 220 = 5125299556163 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5125300604694 and 5125300604703.
It is not an unprimeable number, because it can be changed into a prime (5125300604339) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 36121497 + ... + 36263109.
It is an arithmetic number, because the mean of its divisors is an integer number (95436506880).
Almost surely, 25125300604739 is an apocalyptic number.
5125300604739 is a deficient number, since it is larger than the sum of its proper divisors (4036604055741).
5125300604739 is a wasteful number, since it uses less digits than its factorization.
5125300604739 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 142409 (or 142406 counting only the distinct ones).
The product of its (nonzero) digits is 680400, while the sum is 45.
The spelling of 5125300604739 in words is "five trillion, one hundred twenty-five billion, three hundred million, six hundred four thousand, seven hundred thirty-nine".
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