Base | Representation |
---|---|
bin | 1001100010111111… |
… | …01001100000101101 |
3 | 111020012020121211111 |
4 | 10301133221200231 |
5 | 40444042103443 |
6 | 2204325552021 |
7 | 241003506466 |
oct | 46137514055 |
9 | 14205217744 |
10 | 5125347373 |
11 | 21a0141383 |
12 | bb0575611 |
13 | 638b08733 |
14 | 3689add6d |
15 | 1eee6669d |
hex | 1317e982d |
5125347373 has 2 divisors, whose sum is σ = 5125347374. Its totient is φ = 5125347372.
The previous prime is 5125347251. The next prime is 5125347431. The reversal of 5125347373 is 3737435215.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3153720964 + 1971626409 = 56158^2 + 44403^2 .
It is a cyclic number.
It is not a de Polignac number, because 5125347373 - 217 = 5125216301 is a prime.
It is a super-2 number, since 2×51253473732 = 52538371387836002258, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5125342373) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2562673686 + 2562673687.
It is an arithmetic number, because the mean of its divisors is an integer number (2562673687).
Almost surely, 25125347373 is an apocalyptic number.
It is an amenable number.
5125347373 is a deficient number, since it is larger than the sum of its proper divisors (1).
5125347373 is an equidigital number, since it uses as much as digits as its factorization.
5125347373 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 264600, while the sum is 40.
The square root of 5125347373 is about 71591.5314335432. The cubic root of 5125347373 is about 1724.1475727281.
The spelling of 5125347373 in words is "five billion, one hundred twenty-five million, three hundred forty-seven thousand, three hundred seventy-three".
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