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512540040437 is a prime number
BaseRepresentation
bin1110111010101011100…
…01000101110011110101
31210222221210111202210122
413131111301011303311
531344140222243222
61031242503501325
752013135314115
oct7352561056365
91728853452718
10512540040437
11188404544487
1283400757845
1339442146749
141ab4285b045
15d4eb9caa42
hex7755c45cf5

512540040437 has 2 divisors, whose sum is σ = 512540040438. Its totient is φ = 512540040436.

The previous prime is 512540040401. The next prime is 512540040449. The reversal of 512540040437 is 734040045215.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 507949842436 + 4590198001 = 712706^2 + 67751^2 .

It is a cyclic number.

It is not a de Polignac number, because 512540040437 - 212 = 512540036341 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 512540040397 and 512540040406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (512540040487) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256270020218 + 256270020219.

It is an arithmetic number, because the mean of its divisors is an integer number (256270020219).

Almost surely, 2512540040437 is an apocalyptic number.

It is an amenable number.

512540040437 is a deficient number, since it is larger than the sum of its proper divisors (1).

512540040437 is an equidigital number, since it uses as much as digits as its factorization.

512540040437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 67200, while the sum is 35.

The spelling of 512540040437 in words is "five hundred twelve billion, five hundred forty million, forty thousand, four hundred thirty-seven".