Base | Representation |
---|---|
bin | 101111101111000010… |
… | …110101111111001101 |
3 | 11220022001120220102200 |
4 | 233233002311333031 |
5 | 1314432303442201 |
6 | 35313555312113 |
7 | 3463102334631 |
oct | 575702657715 |
9 | 156261526380 |
10 | 51255140301 |
11 | 1a812210592 |
12 | 9b252ab639 |
13 | 4aaaacc1b1 |
14 | 26a32d4dc1 |
15 | 14eeb73386 |
hex | bef0b5fcd |
51255140301 has 24 divisors (see below), whose sum is σ = 80213253120. Its totient is φ = 31412174976.
The previous prime is 51255140273. The next prime is 51255140333. The reversal of 51255140301 is 10304155215.
51255140301 is a `hidden beast` number, since 5 + 1 + 255 + 1 + 403 + 0 + 1 = 666.
It is not a de Polignac number, because 51255140301 - 27 = 51255140173 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51255140381) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3888781 + ... + 3901938.
It is an arithmetic number, because the mean of its divisors is an integer number (3342218880).
Almost surely, 251255140301 is an apocalyptic number.
51255140301 is a gapful number since it is divisible by the number (51) formed by its first and last digit.
It is an amenable number.
51255140301 is a deficient number, since it is larger than the sum of its proper divisors (28958112819).
51255140301 is a wasteful number, since it uses less digits than its factorization.
51255140301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7790785 (or 7790782 counting only the distinct ones).
The product of its (nonzero) digits is 3000, while the sum is 27.
Adding to 51255140301 its reverse (10304155215), we get a palindrome (61559295516).
The spelling of 51255140301 in words is "fifty-one billion, two hundred fifty-five million, one hundred forty thousand, three hundred one".
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