Base | Representation |
---|---|
bin | 1001100011000000… |
… | …10011101010101001 |
3 | 111020012120101200121 |
4 | 10301200103222221 |
5 | 40444113120131 |
6 | 2204333403241 |
7 | 241005126055 |
oct | 46140235251 |
9 | 14205511617 |
10 | 5125520041 |
11 | 21a024a084 |
12 | bb0639521 |
13 | 638b691c5 |
14 | 368a16c65 |
15 | 1eee9c911 |
hex | 131813aa9 |
5125520041 has 2 divisors, whose sum is σ = 5125520042. Its totient is φ = 5125520040.
The previous prime is 5125519969. The next prime is 5125520083. The reversal of 5125520041 is 1400255215.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3204012816 + 1921507225 = 56604^2 + 43835^2 .
It is a cyclic number.
It is not a de Polignac number, because 5125520041 - 217 = 5125388969 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5125519988 and 5125520015.
It is not a weakly prime, because it can be changed into another prime (5125520441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2562760020 + 2562760021.
It is an arithmetic number, because the mean of its divisors is an integer number (2562760021).
Almost surely, 25125520041 is an apocalyptic number.
It is an amenable number.
5125520041 is a deficient number, since it is larger than the sum of its proper divisors (1).
5125520041 is an equidigital number, since it uses as much as digits as its factorization.
5125520041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2000, while the sum is 25.
The square root of 5125520041 is about 71592.7373481417. The cubic root of 5125520041 is about 1724.1669341326.
Adding to 5125520041 its reverse (1400255215), we get a palindrome (6525775256).
The spelling of 5125520041 in words is "five billion, one hundred twenty-five million, five hundred twenty thousand, forty-one".
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