Base | Representation |
---|---|
bin | 10111010011101110010011… |
… | …10101111110111100010111 |
3 | 20201110221201011221201112022 |
4 | 23221313021311332330113 |
5 | 23204231203131140111 |
6 | 301002154512243355 |
7 | 13540032260023136 |
oct | 1351671165767427 |
9 | 221427634851468 |
10 | 51255231115031 |
11 | 1537124881a399 |
12 | 58b973524055b |
13 | 227a469768c28 |
14 | c92aa30c591d |
15 | 5dd3ed59a2db |
hex | 2e9dc9d7ef17 |
51255231115031 has 2 divisors, whose sum is σ = 51255231115032. Its totient is φ = 51255231115030.
The previous prime is 51255231114953. The next prime is 51255231115087. The reversal of 51255231115031 is 13051113255215.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51255231115031 - 214 = 51255231098647 is a prime.
It is a super-2 number, since 2×512552311150312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51255231114982 and 51255231115000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51255231115091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25627615557515 + 25627615557516.
It is an arithmetic number, because the mean of its divisors is an integer number (25627615557516).
Almost surely, 251255231115031 is an apocalyptic number.
51255231115031 is a deficient number, since it is larger than the sum of its proper divisors (1).
51255231115031 is an equidigital number, since it uses as much as digits as its factorization.
51255231115031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22500, while the sum is 35.
The spelling of 51255231115031 in words is "fifty-one trillion, two hundred fifty-five billion, two hundred thirty-one million, one hundred fifteen thousand, thirty-one".
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