Base | Representation |
---|---|
bin | 10111010011101110101100… |
… | …11111111110100100010011 |
3 | 20201110222020222111110112021 |
4 | 23221313112133332210103 |
5 | 23204232122010401011 |
6 | 301002231535312311 |
7 | 13540040445603664 |
oct | 1351672637764423 |
9 | 221428228443467 |
10 | 51255443450131 |
11 | 15371347667948 |
12 | 58b979437b697 |
13 | 227a4a17518bb |
14 | c92ac339936b |
15 | 5dd41203e471 |
hex | 2e9dd67fe913 |
51255443450131 has 2 divisors, whose sum is σ = 51255443450132. Its totient is φ = 51255443450130.
The previous prime is 51255443450119. The next prime is 51255443450143. The reversal of 51255443450131 is 13105434455215.
It is a balanced prime because it is at equal distance from previous prime (51255443450119) and next prime (51255443450143).
It is a cyclic number.
It is not a de Polignac number, because 51255443450131 - 225 = 51255409895699 is a prime.
It is a super-2 number, since 2×512554434501312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51255443453131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25627721725065 + 25627721725066.
It is an arithmetic number, because the mean of its divisors is an integer number (25627721725066).
Almost surely, 251255443450131 is an apocalyptic number.
51255443450131 is a deficient number, since it is larger than the sum of its proper divisors (1).
51255443450131 is an equidigital number, since it uses as much as digits as its factorization.
51255443450131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720000, while the sum is 43.
The spelling of 51255443450131 in words is "fifty-one trillion, two hundred fifty-five billion, four hundred forty-three million, four hundred fifty thousand, one hundred thirty-one".
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