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5126085684133 is a prime number
BaseRepresentation
bin100101010011000001010…
…0001000010101110100101
3200011001022201120112010021
41022212002201002232211
51132441210413343013
614522520302155141
71036230116251651
oct112460241025645
920131281515107
105126085684133
1116a6a628061a7
126a9577882ab1
132b2507017a5b
1413a165043a61
158d51bad7a8d
hex4a982842ba5

5126085684133 has 2 divisors, whose sum is σ = 5126085684134. Its totient is φ = 5126085684132.

The previous prime is 5126085684079. The next prime is 5126085684169. The reversal of 5126085684133 is 3314865806215.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2624506921089 + 2501578763044 = 1620033^2 + 1581638^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5126085684133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5126085184133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2563042842066 + 2563042842067.

It is an arithmetic number, because the mean of its divisors is an integer number (2563042842067).

Almost surely, 25126085684133 is an apocalyptic number.

It is an amenable number.

5126085684133 is a deficient number, since it is larger than the sum of its proper divisors (1).

5126085684133 is an equidigital number, since it uses as much as digits as its factorization.

5126085684133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4147200, while the sum is 52.

The spelling of 5126085684133 in words is "five trillion, one hundred twenty-six billion, eighty-five million, six hundred eighty-four thousand, one hundred thirty-three".