Base | Representation |
---|---|
bin | 101111101111101001… |
… | …111111110000100101 |
3 | 11220022202220100111111 |
4 | 233233221333300211 |
5 | 1314442420411231 |
6 | 35315003305021 |
7 | 3463255513033 |
oct | 575751776045 |
9 | 156282810444 |
10 | 51265403941 |
11 | 1a817a90834 |
12 | 9b2881b171 |
13 | 4aacc83a5b |
14 | 26a4807553 |
15 | 15009ee4b1 |
hex | befa7fc25 |
51265403941 has 2 divisors, whose sum is σ = 51265403942. Its totient is φ = 51265403940.
The previous prime is 51265403923. The next prime is 51265403947. The reversal of 51265403941 is 14930456215.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51227532225 + 37871716 = 226335^2 + 6154^2 .
It is a cyclic number.
It is not a de Polignac number, because 51265403941 - 221 = 51263306789 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 51265403894 and 51265403903.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51265403947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25632701970 + 25632701971.
It is an arithmetic number, because the mean of its divisors is an integer number (25632701971).
Almost surely, 251265403941 is an apocalyptic number.
It is an amenable number.
51265403941 is a deficient number, since it is larger than the sum of its proper divisors (1).
51265403941 is an equidigital number, since it uses as much as digits as its factorization.
51265403941 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 40.
The spelling of 51265403941 in words is "fifty-one billion, two hundred sixty-five million, four hundred three thousand, nine hundred forty-one".
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