513000000001 has 2 divisors, whose sum is σ = 513000000002. Its totient is φ = 513000000000.

The previous prime is 512999999957. The next prime is 513000000049. The reversal of 513000000001 is 100000000315.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 512764837776 + 235162225 = 716076^2 + 15335^2 .

It is a cyclic number.

It is not a de Polignac number, because 513000000001 - 2¹¹ = 512999997953 is a prime.

It is not a weakly prime, because it can be changed into another prime (513000000901) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256500000000 + 256500000001.

It is an arithmetic number, because the mean of its divisors is an integer number (256500000001).

Almost surely, 2^513000000001 is an apocalyptic number.

It is an amenable number.

513000000001 is a deficient number, since it is larger than the sum of its proper divisors (1).

513000000001 is an equidigital number, since it uses as much as digits as its factorization.

513000000001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15, while the sum is 10.

Adding to 513000000001 its reverse (100000000315), we get a palindrome (613000000316).

The spelling of 513000000001 in words is "five hundred thirteen billion, one", and thus it is an aban number.