Base | Representation |
---|---|
bin | 1110111011100010011… |
… | …01110100001001110101 |
3 | 1211001010220001100012012 |
4 | 13131301031310021311 |
5 | 31401111120231000 |
6 | 1031400314134005 |
7 | 52030426525412 |
oct | 7356115641165 |
9 | 1731126040165 |
10 | 513000555125 |
11 | 188620491a33 |
12 | 8350aa21305 |
13 | 394b6685346 |
14 | 1ab87a95109 |
15 | d527144735 |
hex | 7771374275 |
513000555125 has 8 divisors (see below), whose sum is σ = 640224692952. Its totient is φ = 410400444000.
The previous prime is 513000555113. The next prime is 513000555181. The reversal of 513000555125 is 521555000315.
It can be written as a sum of positive squares in 4 ways, for example, as 2048648644 + 510951906481 = 45262^2 + 714809^2 .
It is not a de Polignac number, because 513000555125 - 224 = 512983777909 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 513000555091 and 513000555100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2052002096 + ... + 2052002345.
It is an arithmetic number, because the mean of its divisors is an integer number (80028086619).
Almost surely, 2513000555125 is an apocalyptic number.
It is an amenable number.
513000555125 is a deficient number, since it is larger than the sum of its proper divisors (127224137827).
513000555125 is an equidigital number, since it uses as much as digits as its factorization.
513000555125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4104004456 (or 4104004446 counting only the distinct ones).
The product of its (nonzero) digits is 18750, while the sum is 32.
The spelling of 513000555125 in words is "five hundred thirteen billion, five hundred fifty-five thousand, one hundred twenty-five".
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