Base | Representation |
---|---|
bin | 1001100011100010… |
… | …11011111101111001 |
3 | 111020112000112102111 |
4 | 10301301123331321 |
5 | 41001240313424 |
6 | 2205013532321 |
7 | 241061240542 |
oct | 46161337571 |
9 | 14215015374 |
10 | 5130010489 |
11 | 21a283689a |
12 | bb20440a1 |
13 | 639a7c086 |
14 | 3694654c9 |
15 | 200588194 |
hex | 131c5bf79 |
5130010489 has 2 divisors, whose sum is σ = 5130010490. Its totient is φ = 5130010488.
The previous prime is 5130010433. The next prime is 5130010511. The reversal of 5130010489 is 9840100315.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4173160000 + 956850489 = 64600^2 + 30933^2 .
It is a cyclic number.
It is not a de Polignac number, because 5130010489 - 29 = 5130009977 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5130010489.
It is not a weakly prime, because it can be changed into another prime (5130010189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2565005244 + 2565005245.
It is an arithmetic number, because the mean of its divisors is an integer number (2565005245).
Almost surely, 25130010489 is an apocalyptic number.
It is an amenable number.
5130010489 is a deficient number, since it is larger than the sum of its proper divisors (1).
5130010489 is an equidigital number, since it uses as much as digits as its factorization.
5130010489 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 31.
The square root of 5130010489 is about 71624.0915404866. The cubic root of 5130010489 is about 1724.6702991248.
The spelling of 5130010489 in words is "five billion, one hundred thirty million, ten thousand, four hundred eighty-nine".
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