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5130010511 is a prime number
BaseRepresentation
bin1001100011100010…
…11011111110001111
3111020112000112110022
410301301123332033
541001240314021
62205013532355
7241061240603
oct46161337617
914215015408
105130010511
1121a283690a
12bb20440bb
13639a7c0a2
14369465503
152005881ab
hex131c5bf8f

5130010511 has 2 divisors, whose sum is σ = 5130010512. Its totient is φ = 5130010510.

The previous prime is 5130010489. The next prime is 5130010519. The reversal of 5130010511 is 1150100315.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5130010511 - 226 = 5062901647 is a prime.

It is a super-2 number, since 2×51300105112 = 52634015685940962242, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 5130010511.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5130010519) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2565005255 + 2565005256.

It is an arithmetic number, because the mean of its divisors is an integer number (2565005256).

Almost surely, 25130010511 is an apocalyptic number.

5130010511 is a deficient number, since it is larger than the sum of its proper divisors (1).

5130010511 is an equidigital number, since it uses as much as digits as its factorization.

5130010511 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 75, while the sum is 17.

The square root of 5130010511 is about 71624.0916940662. The cubic root of 5130010511 is about 1724.6703015902.

Adding to 5130010511 its reverse (1150100315), we get a palindrome (6280110826).

The spelling of 5130010511 in words is "five billion, one hundred thirty million, ten thousand, five hundred eleven".