Base | Representation |
---|---|
bin | 1001100011100011… |
… | …00011001101010111 |
3 | 111020112002001010002 |
4 | 10301301203031113 |
5 | 41001242241101 |
6 | 2205014321515 |
7 | 241061423165 |
oct | 46161431527 |
9 | 14215061102 |
10 | 5130040151 |
11 | 21a2857105 |
12 | bb205929b |
13 | 639a8c722 |
14 | 369472235 |
15 | 200591d6b |
hex | 131c63357 |
5130040151 has 2 divisors, whose sum is σ = 5130040152. Its totient is φ = 5130040150.
The previous prime is 5130040099. The next prime is 5130040187. The reversal of 5130040151 is 1510400315.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5130040151 - 26 = 5130040087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5130048151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2565020075 + 2565020076.
It is an arithmetic number, because the mean of its divisors is an integer number (2565020076).
Almost surely, 25130040151 is an apocalyptic number.
5130040151 is a deficient number, since it is larger than the sum of its proper divisors (1).
5130040151 is an equidigital number, since it uses as much as digits as its factorization.
5130040151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 300, while the sum is 20.
The square root of 5130040151 is about 71624.2986073860. The cubic root of 5130040151 is about 1724.6736231642.
Adding to 5130040151 its reverse (1510400315), we get a palindrome (6640440466).
The spelling of 5130040151 in words is "five billion, one hundred thirty million, forty thousand, one hundred fifty-one".
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