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51301140131022 = 2317947766424703
BaseRepresentation
bin10111010101000011110100…
…01110111110110011001110
320201122100012122212101002220
423222201322032332303032
523211004213333143042
6301035230214000210
713543246035150615
oct1352417216766316
9221570178771086
1051301140131022
1115389767205621
125906608046066
1322818a4aac452
14c94dba37a87c
155de6d8be68ec
hex2ea87a3becce

51301140131022 has 16 divisors (see below), whose sum is σ = 103175477360640. Its totient is φ = 17004847193912.

The previous prime is 51301140130939. The next prime is 51301140131041. The reversal of 51301140131022 is 22013104110315.

It is a junction number, because it is equal to n+sod(n) for n = 51301140130983 and 51301140131001.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23883211278 + ... + 23883213425.

It is an arithmetic number, because the mean of its divisors is an integer number (6448467335040).

Almost surely, 251301140131022 is an apocalyptic number.

51301140131022 is an abundant number, since it is smaller than the sum of its proper divisors (51874337229618).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

51301140131022 is a wasteful number, since it uses less digits than its factorization.

51301140131022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47766424887.

The product of its (nonzero) digits is 720, while the sum is 24.

Adding to 51301140131022 its reverse (22013104110315), we get a palindrome (73314244241337).

The spelling of 51301140131022 in words is "fifty-one trillion, three hundred one billion, one hundred forty million, one hundred thirty-one thousand, twenty-two".

Divisors: 1 2 3 6 179 358 537 1074 47766424703 95532849406 143299274109 286598548218 8550190021837 17100380043674 25650570065511 51301140131022