Base | Representation |
---|---|
bin | 10111010101000101011100… |
… | …00001001010101011100100 |
3 | 20201122102110012122200020221 |
4 | 23222202232001022223210 |
5 | 23211013003241044100 |
6 | 301035452331134124 |
7 | 13543306414605436 |
oct | 1352425601125344 |
9 | 221572405580227 |
10 | 51302008924900 |
11 | 1538a072663298 |
12 | 590680aba4344 |
13 | 22819b2a9ab76 |
14 | c9505d8d2656 |
15 | 5de73a10c01a |
hex | 2ea8ae04aae4 |
51302008924900 has 36 divisors (see below), whose sum is σ = 111329706286512. Its totient is φ = 20520002294560.
The previous prime is 51302008924867. The next prime is 51302008924937. The reversal of 51302008924900 is 942980020315.
It is a super-3 number, since 3×513020089249003 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7438822 + ... + 12567421.
It is an arithmetic number, because the mean of its divisors is an integer number (3092491841292).
Almost surely, 251302008924900 is an apocalyptic number.
51302008924900 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
51302008924900 is an abundant number, since it is smaller than the sum of its proper divisors (60027697361612).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51302008924900 is a wasteful number, since it uses less digits than its factorization.
51302008924900 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20031900 (or 20031893 counting only the distinct ones).
The product of its (nonzero) digits is 155520, while the sum is 43.
The spelling of 51302008924900 in words is "fifty-one trillion, three hundred two billion, eight million, nine hundred twenty-four thousand, nine hundred".
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