Base | Representation |
---|---|
bin | 101111110001111001… |
… | …100001111000100011 |
3 | 11220102101200222011121 |
4 | 233301321201320203 |
5 | 1320032033432212 |
6 | 35322425553111 |
7 | 3464223363634 |
oct | 576171417043 |
9 | 156371628147 |
10 | 51303030307 |
11 | 1a837250001 |
12 | 9b39345797 |
13 | 4ab79c9089 |
14 | 26a97dd88b |
15 | 1503e82d07 |
hex | bf1e61e23 |
51303030307 has 2 divisors, whose sum is σ = 51303030308. Its totient is φ = 51303030306.
The previous prime is 51303030283. The next prime is 51303030413. The reversal of 51303030307 is 70303030315.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51303030307 - 215 = 51302997539 is a prime.
It is a super-3 number, since 3×513030303073 (a number of 33 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (51303030007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25651515153 + 25651515154.
It is an arithmetic number, because the mean of its divisors is an integer number (25651515154).
Almost surely, 251303030307 is an apocalyptic number.
51303030307 is a deficient number, since it is larger than the sum of its proper divisors (1).
51303030307 is an equidigital number, since it uses as much as digits as its factorization.
51303030307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2835, while the sum is 25.
The spelling of 51303030307 in words is "fifty-one billion, three hundred three million, thirty thousand, three hundred seven".
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