Base | Representation |
---|---|
bin | 10111010101001001001101… |
… | …01011110010100001110011 |
3 | 20201122121200021222211201221 |
4 | 23222210212223302201303 |
5 | 23211031130020122313 |
6 | 301040425250005511 |
7 | 13543410526215463 |
oct | 1352444653624163 |
9 | 221577607884657 |
10 | 51304033364083 |
11 | 1538aa11382425 |
12 | 5907094b76897 |
13 | 2281c46321086 |
14 | c951b270dba3 |
15 | 5de807beac8d |
hex | 2ea926af2873 |
51304033364083 has 8 divisors (see below), whose sum is σ = 52272217338768. Its totient is φ = 50335856180064.
The previous prime is 51304033364057. The next prime is 51304033364113. The reversal of 51304033364083 is 38046333040315.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51304033364083 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51304033364033) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15110616 + ... + 18191722.
It is an arithmetic number, because the mean of its divisors is an integer number (6534027167346).
Almost surely, 251304033364083 is an apocalyptic number.
51304033364083 is a gapful number since it is divisible by the number (53) formed by its first and last digit.
51304033364083 is a deficient number, since it is larger than the sum of its proper divisors (968183974685).
51304033364083 is a wasteful number, since it uses less digits than its factorization.
51304033364083 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3395333.
The product of its (nonzero) digits is 933120, while the sum is 43.
The spelling of 51304033364083 in words is "fifty-one trillion, three hundred four billion, thirty-three million, three hundred sixty-four thousand, eighty-three".
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