Base | Representation |
---|---|
bin | 11110100101000… |
… | …110100000000001 |
3 | 1022202101020220121 |
4 | 132211012200001 |
5 | 2022314324213 |
6 | 122524140241 |
7 | 15466534351 |
oct | 3645064001 |
9 | 1282336817 |
10 | 513042433 |
11 | 243665412 |
12 | 123997681 |
13 | 823a0707 |
14 | 4c1ccb61 |
15 | 3009288d |
hex | 1e946801 |
513042433 has 2 divisors, whose sum is σ = 513042434. Its totient is φ = 513042432.
The previous prime is 513042373. The next prime is 513042437. The reversal of 513042433 is 334240315.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 506115009 + 6927424 = 22497^2 + 2632^2 .
It is a cyclic number.
It is not a de Polignac number, because 513042433 - 213 = 513034241 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 513042398 and 513042407.
It is not a weakly prime, because it can be changed into another prime (513042437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256521216 + 256521217.
It is an arithmetic number, because the mean of its divisors is an integer number (256521217).
Almost surely, 2513042433 is an apocalyptic number.
It is an amenable number.
513042433 is a deficient number, since it is larger than the sum of its proper divisors (1).
513042433 is an equidigital number, since it uses as much as digits as its factorization.
513042433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 25.
The square root of 513042433 is about 22650.4400178010. The cubic root of 513042433 is about 800.5425657989.
Adding to 513042433 its reverse (334240315), we get a palindrome (847282748).
The spelling of 513042433 in words is "five hundred thirteen million, forty-two thousand, four hundred thirty-three".
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