Base | Representation |
---|---|
bin | 1110111011101000001… |
… | …10000000100000111101 |
3 | 1211001021020220110221021 |
4 | 13131310012000200331 |
5 | 31401211000342003 |
6 | 1031405201104141 |
7 | 52031554121365 |
oct | 7356406004075 |
9 | 1731236813837 |
10 | 513048840253 |
11 | 1886457712a4 |
12 | 83523028051 |
13 | 394c3690021 |
14 | 1ab902639a5 |
15 | d52b4d12bd |
hex | 777418083d |
513048840253 has 2 divisors, whose sum is σ = 513048840254. Its totient is φ = 513048840252.
The previous prime is 513048840233. The next prime is 513048840319. The reversal of 513048840253 is 352048840315.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 299644570404 + 213404269849 = 547398^2 + 461957^2 .
It is a cyclic number.
It is not a de Polignac number, because 513048840253 - 29 = 513048839741 is a prime.
It is a super-2 number, since 2×5130488402532 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (513048840233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256524420126 + 256524420127.
It is an arithmetic number, because the mean of its divisors is an integer number (256524420127).
Almost surely, 2513048840253 is an apocalyptic number.
It is an amenable number.
513048840253 is a deficient number, since it is larger than the sum of its proper divisors (1).
513048840253 is an equidigital number, since it uses as much as digits as its factorization.
513048840253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 460800, while the sum is 43.
The spelling of 513048840253 in words is "five hundred thirteen billion, forty-eight million, eight hundred forty thousand, two hundred fifty-three".
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