Base | Representation |
---|---|
bin | 101111110010011010… |
… | …010000110110111111 |
3 | 11220102222211221010011 |
4 | 233302122100312333 |
5 | 1320041233030302 |
6 | 35323333524051 |
7 | 3464356333324 |
oct | 576232206677 |
9 | 156388757104 |
10 | 51311611327 |
11 | 1a841081059 |
12 | 9b401a3627 |
13 | 4ab9711ac2 |
14 | 26aa9d4b4b |
15 | 1504aca5d7 |
hex | bf2690dbf |
51311611327 has 2 divisors, whose sum is σ = 51311611328. Its totient is φ = 51311611326.
The previous prime is 51311611313. The next prime is 51311611349. The reversal of 51311611327 is 72311611315.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51311611327 - 227 = 51177393599 is a prime.
It is a super-2 number, since 2×513116113272 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51311611357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25655805663 + 25655805664.
It is an arithmetic number, because the mean of its divisors is an integer number (25655805664).
Almost surely, 251311611327 is an apocalyptic number.
51311611327 is a deficient number, since it is larger than the sum of its proper divisors (1).
51311611327 is an equidigital number, since it uses as much as digits as its factorization.
51311611327 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3780, while the sum is 31.
The spelling of 51311611327 in words is "fifty-one billion, three hundred eleven million, six hundred eleven thousand, three hundred twenty-seven".
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