Base | Representation |
---|---|
bin | 100101010101011100101… |
… | …1100101011010111100011 |
3 | 200011112210021110201202112 |
4 | 1022222321130223113203 |
5 | 1133032401334112201 |
6 | 14525142051305535 |
7 | 1036503311335421 |
oct | 112527134532743 |
9 | 20145707421675 |
10 | 5131302254051 |
11 | 16a919a393406 |
12 | 6aa5928ab2ab |
13 | 2b2b589b2a0c |
14 | 13a4dbb9c111 |
15 | 8d724a6d0bb |
hex | 4aab972b5e3 |
5131302254051 has 2 divisors, whose sum is σ = 5131302254052. Its totient is φ = 5131302254050.
The previous prime is 5131302253967. The next prime is 5131302254077. The reversal of 5131302254051 is 1504522031315.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5131302254051 - 214 = 5131302237667 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 5131302253999 and 5131302254017.
It is not a weakly prime, because it can be changed into another prime (5131302259051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2565651127025 + 2565651127026.
It is an arithmetic number, because the mean of its divisors is an integer number (2565651127026).
Almost surely, 25131302254051 is an apocalyptic number.
5131302254051 is a deficient number, since it is larger than the sum of its proper divisors (1).
5131302254051 is an equidigital number, since it uses as much as digits as its factorization.
5131302254051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 5131302254051 its reverse (1504522031315), we get a palindrome (6635824285366).
The spelling of 5131302254051 in words is "five trillion, one hundred thirty-one billion, three hundred two million, two hundred fifty-four thousand, fifty-one".
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