Base | Representation |
---|---|
bin | 101111110010100000… |
… | …011000101110110001 |
3 | 11220110002212110220112 |
4 | 233302200120232301 |
5 | 1320042140411213 |
6 | 35323432151105 |
7 | 3464406100043 |
oct | 576240305661 |
9 | 156402773815 |
10 | 51313216433 |
11 | 1a841a77a96 |
12 | 9b40838495 |
13 | 4ab9b5457b |
14 | 26aacd1a93 |
15 | 1504ce5ea8 |
hex | bf2818bb1 |
51313216433 has 2 divisors, whose sum is σ = 51313216434. Its totient is φ = 51313216432.
The previous prime is 51313216393. The next prime is 51313216439. The reversal of 51313216433 is 33461231315.
51313216433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 40494720289 + 10818496144 = 201233^2 + 104012^2 .
It is a cyclic number.
It is not a de Polignac number, because 51313216433 - 222 = 51309022129 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 51313216433.
It is not a weakly prime, because it can be changed into another prime (51313216439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25656608216 + 25656608217.
It is an arithmetic number, because the mean of its divisors is an integer number (25656608217).
Almost surely, 251313216433 is an apocalyptic number.
It is an amenable number.
51313216433 is a deficient number, since it is larger than the sum of its proper divisors (1).
51313216433 is an equidigital number, since it uses as much as digits as its factorization.
51313216433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 19440, while the sum is 32.
Adding to 51313216433 its reverse (33461231315), we get a palindrome (84774447748).
The spelling of 51313216433 in words is "fifty-one billion, three hundred thirteen million, two hundred sixteen thousand, four hundred thirty-three".
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