Base | Representation |
---|---|
bin | 1110111011110100100… |
… | …11011010000110011001 |
3 | 1211001112111221011111022 |
4 | 13131322103122012121 |
5 | 31401414133004332 |
6 | 1031423402012225 |
7 | 52034260445402 |
oct | 7357223320631 |
9 | 1731474834438 |
10 | 513153016217 |
11 | 188699555236 |
12 | 83551aa7075 |
13 | 3950c1364ca |
14 | 1aba00209a9 |
15 | d53570d212 |
hex | 777a4da199 |
513153016217 has 2 divisors, whose sum is σ = 513153016218. Its totient is φ = 513153016216.
The previous prime is 513153016213. The next prime is 513153016219. The reversal of 513153016217 is 712610351315.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 404611760281 + 108541255936 = 636091^2 + 329456^2 .
It is a cyclic number.
It is not a de Polignac number, because 513153016217 - 22 = 513153016213 is a prime.
Together with 513153016219, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (513153016213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256576508108 + 256576508109.
It is an arithmetic number, because the mean of its divisors is an integer number (256576508109).
Almost surely, 2513153016217 is an apocalyptic number.
It is an amenable number.
513153016217 is a deficient number, since it is larger than the sum of its proper divisors (1).
513153016217 is an equidigital number, since it uses as much as digits as its factorization.
513153016217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18900, while the sum is 35.
The spelling of 513153016217 in words is "five hundred thirteen billion, one hundred fifty-three million, sixteen thousand, two hundred seventeen".
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