Base | Representation |
---|---|
bin | 1001100011110000… |
… | …00000111011010001 |
3 | 111020122021010122112 |
4 | 10301320000323101 |
5 | 41002211002422 |
6 | 2205114515105 |
7 | 241112011523 |
oct | 46170007321 |
9 | 14218233575 |
10 | 5131734737 |
11 | 21a3804298 |
12 | bb2735a95 |
13 | 63a233b3c |
14 | 369793a13 |
15 | 2007c8ee2 |
hex | 131e00ed1 |
5131734737 has 2 divisors, whose sum is σ = 5131734738. Its totient is φ = 5131734736.
The previous prime is 5131734731. The next prime is 5131734743. The reversal of 5131734737 is 7374371315.
It is a balanced prime because it is at equal distance from previous prime (5131734731) and next prime (5131734743).
It can be written as a sum of positive squares in only one way, i.e., 2941869121 + 2189865616 = 54239^2 + 46796^2 .
It is a cyclic number.
It is not a de Polignac number, because 5131734737 - 28 = 5131734481 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5131734694 and 5131734703.
It is not a weakly prime, because it can be changed into another prime (5131734731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2565867368 + 2565867369.
It is an arithmetic number, because the mean of its divisors is an integer number (2565867369).
Almost surely, 25131734737 is an apocalyptic number.
It is an amenable number.
5131734737 is a deficient number, since it is larger than the sum of its proper divisors (1).
5131734737 is an equidigital number, since it uses as much as digits as its factorization.
5131734737 is an evil number, because the sum of its binary digits is even.
The product of its digits is 185220, while the sum is 41.
The square root of 5131734737 is about 71636.1273171575. The cubic root of 5131734737 is about 1724.8635038114.
The spelling of 5131734737 in words is "five billion, one hundred thirty-one million, seven hundred thirty-four thousand, seven hundred thirty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •