Base | Representation |
---|---|
bin | 100101010101110100111… |
… | …0101101100110101010001 |
3 | 200011121212212010210111101 |
4 | 1022223221311230311101 |
5 | 1133041032203320032 |
6 | 14525354412344401 |
7 | 1036532400152533 |
oct | 112535165546521 |
9 | 20147785123441 |
10 | 5132114120017 |
11 | 16a9576699315 |
12 | 6aa77a775101 |
13 | 2b2c57c5b891 |
14 | 13a577935853 |
15 | 8d770e8ade7 |
hex | 4aae9d6cd51 |
5132114120017 has 2 divisors, whose sum is σ = 5132114120018. Its totient is φ = 5132114120016.
The previous prime is 5132114119991. The next prime is 5132114120033. The reversal of 5132114120017 is 7100214112315.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4534957647936 + 597156472081 = 2129544^2 + 772759^2 .
It is a cyclic number.
It is not a de Polignac number, because 5132114120017 - 223 = 5132105731409 is a prime.
It is not a weakly prime, because it can be changed into another prime (5132114120417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2566057060008 + 2566057060009.
It is an arithmetic number, because the mean of its divisors is an integer number (2566057060009).
Almost surely, 25132114120017 is an apocalyptic number.
It is an amenable number.
5132114120017 is a deficient number, since it is larger than the sum of its proper divisors (1).
5132114120017 is an equidigital number, since it uses as much as digits as its factorization.
5132114120017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1680, while the sum is 28.
The spelling of 5132114120017 in words is "five trillion, one hundred thirty-two billion, one hundred fourteen million, one hundred twenty thousand, seventeen".
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