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5132114120033 is a prime number
BaseRepresentation
bin100101010101110100111…
…0101101100110101100001
3200011121212212010210111222
41022223221311230311201
51133041032203320113
614525354412344425
71036532400152555
oct112535165546541
920147785123458
105132114120033
1116a957669932a
126aa77a775115
132b2c57c5b8a4
1413a577935865
158d770e8ae08
hex4aae9d6cd61

5132114120033 has 2 divisors, whose sum is σ = 5132114120034. Its totient is φ = 5132114120032.

The previous prime is 5132114120017. The next prime is 5132114120039. The reversal of 5132114120033 is 3300214112315.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4770519959104 + 361594160929 = 2184152^2 + 601327^2 .

It is a cyclic number.

It is not a de Polignac number, because 5132114120033 - 24 = 5132114120017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5132114119984 and 5132114120011.

It is not a weakly prime, because it can be changed into another prime (5132114120039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2566057060016 + 2566057060017.

It is an arithmetic number, because the mean of its divisors is an integer number (2566057060017).

Almost surely, 25132114120033 is an apocalyptic number.

It is an amenable number.

5132114120033 is a deficient number, since it is larger than the sum of its proper divisors (1).

5132114120033 is an equidigital number, since it uses as much as digits as its factorization.

5132114120033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 5132114120033 its reverse (3300214112315), we get a palindrome (8432328232348).

The spelling of 5132114120033 in words is "five trillion, one hundred thirty-two billion, one hundred fourteen million, one hundred twenty thousand, thirty-three".